Confirm by calculation that an energy of 5.02 MeV will

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Confirm by calculation that an energy of 5.02 MeV will be released in the nuclear reaction 6Li3 2H1 = 7Li3 1H1.

Task 60541. Detailed solution with a brief record of the conditions, formulas and laws used in the decision, the conclusion of the calculation formula and the answer.
If you have any questions about the decision, write. I will try to help. File in image format.

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